(2+x)(2+x)=1+x^2

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Solution for (2+x)(2+x)=1+x^2 equation:


Simplifying
(2 + x)(2 + x) = 1 + x2

Multiply (2 + x) * (2 + x)
(2(2 + x) + x(2 + x)) = 1 + x2
((2 * 2 + x * 2) + x(2 + x)) = 1 + x2
((4 + 2x) + x(2 + x)) = 1 + x2
(4 + 2x + (2 * x + x * x)) = 1 + x2
(4 + 2x + (2x + x2)) = 1 + x2

Combine like terms: 2x + 2x = 4x
(4 + 4x + x2) = 1 + x2

Add '-1x2' to each side of the equation.
4 + 4x + x2 + -1x2 = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
4 + 4x + 0 = 1 + x2 + -1x2
4 + 4x = 1 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
4 + 4x = 1 + 0
4 + 4x = 1

Solving
4 + 4x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 4x = 1 + -4

Combine like terms: 4 + -4 = 0
0 + 4x = 1 + -4
4x = 1 + -4

Combine like terms: 1 + -4 = -3
4x = -3

Divide each side by '4'.
x = -0.75

Simplifying
x = -0.75

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